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\begin{document}

\frame{\frametitle{\b Newton's Laws I-1 } \bigskip

{\bf Superposition of forces (1).} \bigskip

Trick question! Forces have to cancel when the velocity is constant. 
Therefore, the velocity is not needed.
$$ \vec{F}_3 = -\vec{F}_1 - \vec{F}_2\,. $$
%\bigskip

{\bf Forces (2):} Friction is neglected in this problem.  \bigskip

{\bf Concorde (3):} $v=a\,t~~\Rightarrow~~t\,,~~x = f(t)\,,~~f(t)=?$.
\bigskip

{\bf Force needed (4):} % \bigskip
$$ a = \frac{v}{t}\,,~~F = m\,a\,,~~x=\frac{v}{2}\,t\,.$$

{\bf Penguin: (5):} 
$$ v_y = t\,\frac{F_y}{m}\,.$$ % \bigskip
\vskip 20pt }


\frame{\frametitle{\b Newton's Laws I-2 } \bigskip

{\bf Frozen Lake (6):} 
$$ a=\frac{F}{m}~~~(a\,,~F~{\rm magnitudes)}\,.$$
\bigskip

\bigskip {\bf Motion and Forces (7):} % \bigskip

$$ v_x=a_x\,t\,,~~~a_x=\frac{F_x}{m}\,. $$
\vskip 20pt }

\end{document}
